Tolong di bantu kakak² yg baik hati

Jawaban:

Besar angle DBC∠DBC

→ (180° – 80°) ÷ 2

→ 100° ÷ 2

→ 50°

Besar angle ABD∠ABD

tt = frac{4}{5} times {50}^{ circ}=

5

4

×50

∘

tt = { frac{200}{5} }^{ circ}=

5

200

∘

= 40°

Besar tt angle A∠A

→ 360° – (80° + 2(50° + 40°))

→ 360° – (80° + 2(90°))

→ 360° – (80° + 180°)

→ 360° – 260°

→ 100°

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⋆ JK⋆