Tolong di jawab makasih​

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Tolong di jawab makasih​

Tolong di jawab makasih​

1.

2 sin( 2x - 60 ) {}^{0} - sqrt{3} = 0 \ 2 sin(2x - 60) {}^{0} = sqrt{3} \ sin(2x - 60) {}^{0} = frac{1}{2} sqrt{3} \

sin ( 2x – 60 )° = sin 60°

( 2x – 60 )° = 60° + k.360°

2x = 120° + k.360°

x = 60° + k.180°

k = 0——> x1 = 60° + 0.180° = 60°

k = 1 ——> x3 = 60° + 1.180° = 240°

k = 2 —–> x5 = 60° + 2.180° = 420° ( TM )

( 2x – 60 )° = ( 180° – 60° ) + k.360°

( 2x – 60 )° = 120° + k.360°

2x = 180° + k.360°

x = 90° + k.180°

k = 0 ——> x2 = 90° + 0.180° = 90°

k = 1 ——-> x4 = 90° + 1.180° = 270°

k = 2 ——> x6 = 90° + 2.180° = 450° ( TM )

HP = { 60°, 90°, 240°, 270° }