Tolong di jawab ya…

Dik : m1 = 1 kg
        m2 = 2 kg
        Δt1 = 90'C
        Δt2 = 60'C
        C1 = C2
Dit : t campuran ?
Jwb :
m1.c1.Δt1 = m2.c2.Δt2
1 kg.(90'C – t campuran) = 2 kg.(t campuran – 60'C)
90 kg'C – 1 kg t campuran = 2 kg t campuran – 120 kg'C
90 kg'C + 120 kg'C = 2 kg t campuran + 1 kg t campuran
210 kg'C = 3 kg t campuran
t campuran = 210'C / 3
                 = 70'C

maaf ya kalau salah

Qserap = Q lepas
m.c.ΔT.tinggi = m.c.ΔT.rendah
1.1.(90-x) = 2.1.(x-60) => anggap suhu campuran x
90 – x = 2x – 120
210 = 3x
x=70