Tolong di jawab ya kak...kelas 10 smk

Tolong di jawab ya kak…kelas 10 smk

Nyoba Jawab

AC² = AB² + BC²

AC² = 24² + 7²

AC² = 576 + 49

AC² = 625

AC = √625

AC = 25

sin α = BC/AC = 7/25

cos α = AB/AC = 24/25

tan α = BC/AB = 7/24

cosecan α = AC/BC = 25/7

secan α = AC/AB = 25/24

cotangen α = AB/BC = 24/7

tan α = 0,75 = 3/4

y = 3

x = 4

r² = x² + y²

r² = 4² + 3²

r² = 16 + 9

r² = 25

r = √25

r = 5

a. sin α = y/r = 3/5

b. cos α = x/r = 4/5

c. secan α = r/x = 5/4

d. cotangen α = x/y = 4/3

e. cosecan α = r/y = 5/3

1. $sin alpha = frac{BC}{AC}\sin alpha =frac{7}{sqrt{7^{2} + 24^{2} } }\sin alpha = frac{7}{25}\\cosalpha= frac{AB}{AC}\cosalpha =frac{24}{25}\\tanalpha = frac{BC}{AB}\tanalpha= frac{7}{24}$

$cscalpha=frac{1}{sinalpha}\cscalpha=frac{25}{7}\\secalpha =frac{1}{cosalpha}\secalpha =frac{25}{24}\\\cotalpha =frac{1}{tanalpha}\\cotalpha =frac{24}{7}$