Tolong di jwab ya kaaa​

Jawab:

gradien  g = m1 = 5/3

gradien  garis tegak lurus  g = m2 = – 1/m1 = – 3/5

melalui A (1,-2) ,

pers  garis  y – y1  = m( x- x1)

y + 2 = – 3/5 ( x – 1)

5(y +2)  = – 3 (x – 1)

5y +10 =-  3x+  3

3x + 5y =  3- 10

3x  + 5y = – 7