Tolong dibantu dong dua soal ini soalnya susah makasih

Tolong dibantu dong dua soal ini soalnya susah makasih

Jawaban Terkonfirmasi

No. 1
BF / CF = AB / EF
10 / 15 = 12 / EF
10.EF = 12 × 15
10.EF = 180
EF = 180 / 10
EF = 18

BF / CF = EF / CD
10 / 15 = 18 / CD
10.CD = 18 × 15
10.CD = 270
CD = 270 / 10
CD = 27

CD – EF = 27 – 18 = 9
Tinggi Trapesium adlah DE

$DE= sqrt{(CF)^{2} - (CD-EF)^{2}} \ \ DE= sqrt{15^{2} - 9^{2}} \ \ DE= sqrt{225 - 81} \ \ DE= sqrt{144} = 12 \ \ \ Luas Trapesium \ \ L= frac{1}{2}.(EF + CD).(DE) \ \ L= frac{1}{2}.(18 + 27).(12)\ \ L= frac{1}{2}.(45).(12)\ \ L= (45).(6) \ \ L= 270 \ \ Luas Trapesium EFCD adalah 270 cm^{2}$

No. 2
$Tinggi Kerucut = sqrt{s^{2} -r^{2}} \ Tinggi Kerucut = sqrt{25^{2} -7^{2}} \ Tinggi Kerucut = sqrt{625 -49} \ Tinggi Kerucut = sqrt{576} \ Tinggi Kerucut = 24 \ \ Volume Bandul=Volume frac{1}{2} Bola+Volume Kerucut \ \ V_{B} =( frac{1}{2}. frac{4}{3}. pi .r^{3})+( frac{1}{3}. pi .r^{2}.t) \ \ V_{B} =( frac{1}{2}. frac{4}{3}. frac{22}{7}.7^{3})+( frac{1}{3}.frac{22}{7}.7^{2}.24) \ \ V_{B} = (frac{(2).(22).(49)}{3} ) +((22).(7).(8))$

$V_{B} = (frac{(2).(22).(49)}{3} ) +((22).(7).(8)) \ \V_{B} =718 frac{2}{3}+ 1232 \ \ V_{B} = 1950 frac{2}{3} cm^{3}$