Tolong Dibantu Kakak2

Berarti

h(tetha) = sec(p.tetha +q)⁴

Anggap aja

u = sec (p.tetha + q)

u' = sec (p.tetha +q).tan (p.tetha + q).p

Jadi :

h'(tetha) =

4.(sec(p.tetha +q)³.p.sec (p.tetha + q).tan (p tetha +q) =

4p (sec(p.tetha +q)⁴.tan (p.tetha + q) =

4p.1/cos (sec (p.tetha +q)⁴.(sin/cos ) (p.tetha + q) =

sin 4p (sec (p.tetha + q)⁴ / cos (p.tetha +q)