Tolong dibantu yaa teman2

#F

a) f' (x) = x – 2x⁻²

f(x)= ∫ f ' (x ) dx = ∫ (x- 2x⁻² ) dx = 1/2 x² + 2/x + c

f(2)= 9 –> 1/2 (2)² + 2/2 + c= 9

2 + 1 + c= 9 –> c = 6

f(x) = 1/2 x² + 2x + 6

..

b) f'(x)= 1 – 2x

f(x)= ∫ (1- 2x) dx = x- x² + c

f(3)= 4 –> 3 – 3²+ c= 4 –> 3 -9 + c= 4

-6 + c = 4

c = 10

f(x) = x – x² + 10 atau f(x) = – x² + x + 10