Tolong dibantu yah:))))))

A) f(x) = 5ˣ⁻³
f⁻¹(5ˣ⁻³) = x
f⁻¹(4) =  …
5ˣ⁻³ = 4
x-3 = ⁵log 4
x = ⁵log 4 + 3 = ⁵log4(5³)
x = ⁵log 500

b. f(x) = √ [ (x-1) /(x-8) ] 
f⁻¹(√ [ (x-1)/ (x-8) ] ) = x
f⁻¹(b) = 9
√[(b-1)/(b-8)]  = 9 kuadratkan kedua ruas
(b-1) / (b – 8) = 81
b -1 = 81(b-8)
b -1 = 81 b – 648
-80  b = – 647
b = 647/80

2) h(x) = f(x) . g(x)
domain x²- 4 ≠ 0 atau x – 2 ≥ 0
x ≠ 2 atau x ≠ -2  atau x ≥ 2
Domain x ≥ 2