Tolong dibantu yah kak please.

Orde reaksi NO (pakai [Br2] konstan)
laju ~ 1/waktu
(0,1/0,3)^n = (1/108)/(1/24)
<=> (1/3)^n = 1/9
<=> n = 2
orde Br2 (pakai [NO] konstan)
(0,1/0,2)^m = (1/108)/(1/54)
<=> (1/2)^m = 1/2
<=> m = 1
orde reaksi total = 1 + 2 = 3

semoga membantu