Tolong dijawab ya Kak yang No 1-3 ​

1. jarak pusat = JP = 25 cm

R= 12 cm,. r = 5 cm

panjang GSPL = P, maka

P² = JP² – (R-r)² = 25² – (12-5)²

= 625 – 49 = 576

P = √576 = 24 cm

2. panjang GSPL = P = 24 cm

jarak titik pusat = JP = 30 cm

r = 7 cm

JP² = P² + (R-r)²

30² = 24² + (R-7)²

(R-7)² = 30² – 24² = 900 – 576 = 324

R-7 = √324= 18

R = 18 + 7 = 25 cm

3. R = 9 cm r = 4 cm

AB = 12 cm

a. MN² = AB² + (R-r)² = 12² + (9-4)²

= 144 + 25 = 169

MN =√169 = 13 cm

b. L = 2x (R+r)/2 x AB

= (R+r) x AB = (9+4) x 12

= 13 x 12 = 156 cm²