Tolong dijawab yaa,sama caranya juga OK

By Admin ReiPosted on December 8, 2022

Tolong dijawab yaa,sama caranya juga OK

$AB^2=AC^2+BC^2-2.AC.BC.cos{BCA} \ AB^2 = {10}^{2} + {8}^{2} - 2(10)(8) cos(60) \ AB^2 =100 + 64 - 2(10)(8)( frac{1}{2} ) \ AB = sqrt{164 - 80} \ AB = sqrt{84} \ AB = 2 sqrt{21}$