TOlong dikerjakan

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TOlong dikerjakan

TOlong dikerjakan

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SOAL
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t e r l a m p i r

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DIKETAHUI
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4.
R = 0,5 m
w = F = 75 N

5.
P = 50.000 Pa = 50.000 N/m^2
p = 2 cm = 0,02 m
l = 5 cm = 0,05 m
g = 10 m/s^2

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DITANYA
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4. P = . . . .

5. massa = . . . .

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JAWAB
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4.
A = R×R = 25 × 10 ^ -2 m^2

P = F/A

P = 75/25 × 10 ^ -2

P = 3 × 10^2 = 300 Pa (C)

5.
F = P×A
F = 50.000 × (2×10^ -2 × 5×10^ -2)
F = 5×10^4 × 10 × 10^ -4
F = 50 N

m = F/g = 50/10 = 5 kg

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DETAIL JAWABAN
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■Mapel: Fisika
■Kelas: VIII
■Materi: Tekanan
■Kata Kunci: Massa
■Kode Soal: 2
■Kode Kategorisasi: 8.2.3

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PELAJARI LEBIH LANJUT
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