Tolong dong beserta caranya a dan b

Tolong dong beserta caranya a dan b

Jawaban Terkonfirmasi

Jawab :
a) 3^4x+2 = √3^4/3^x-1
3^4x+2 = √3^4-(-x-1)
3^4x+2 = 3^5-x/2
4x+2 = (5-x)/2
8x-4 = 5-x
x = 1

b)
2^3x+1/2 = √(2^-5)^x-4
2^3x+1/2 = 2^(-5x+20)/2
3x+1/2 = (-5x+20)/2
6x+1 = -5x+20
11x= 19
x= 19/11

Jawaban Terkonfirmasi

Gunakan sifat-sifat perpangkatan yang ada.

Nomor 1.
$$begin{align}9^{2x+1}&=sqrt{frac{81}{3^{x-1}}} \ (3^2)^{2x+1}&=sqrt{3^4times (3^{-1})^{x-1}} \ 3^{2(2x+1)}&=sqrt{3^4times3^{-1(x-1)}} \ 3^{4x+2}&=sqrt{3^{4+(-x+1)}} \ 3^{4x-2}&=sqrt{3^{5-x}} \ (3^{4x-2})^2&=3^{5-x} \ 3^{2(4x-2)}&=3^{5-x} \ 3^{8x-4}&=3^{5-x} \ 8x-4&=5-x \ 8x+x&=5+4 \ 9x&=9 \ x&=1end{align}$

Nomor 2.
$$begin{align}2^{3x+textstylefrac12}&=sqrt{left[frac1{32}right]^{x-4}} \ left(2^{3x+textstylefrac12}right)^2&=left[frac1{32}right]^{x-4} \ 2^{6x+1}&=(2^{-5})^{x-4} \ 2^{6x+1}&=2^{-5x+20} \ 6x+1&=-5x+20 \ 6x+5x&=20-1 \ 11x&=19 \ x&=frac{19}{11} end{align}$