Tolong dong bsok ulangan pake cara ya? Diketahui f(x)=ax+b.f(-2)=-7 Dan f(2) =1 Nilai f (0) adalah?

F(-2) = a×-2+b
-7 = -2a + b

f(2) = a×2 +b
1 = 2a + b

-2a + b = -7
2a + b = 1
0 + 2b = -6
b = -6/2
b = -3

2a + b = 1
2a + -3 = 1
a = 1 + 3 : 2
a = 4/2
a = 2

jadi f(0) = a0 + b
= 2.0 + -3
= 0 + -3
= -3

maaf kalau salah

F(x) = ax + b
f(2) = 2a+b = 1
f(-2) =-2a + b = -7
————————– –
4a = 8
a = 2
substitusikan:
f(2) = 2a+b = 1
2(2)+b = 1
4 + b = 1
b = -3
jadi,
f(0) = ax+b —-> 0(2)+(-3)
= 0-3 = -3
f(0) = -3