Tolong dong cuma 2 soal ini saja​

Penjelasan dengan langkah-langkah:

Turunan

a).

y = x – 2√x

y = x – 2x^½

y' = 1 – 1/2.2x^(1/2 – 1)

y' = 1 – x^-½

y' = 1 – 1/x^½

y' = 1 – 1/√x

b).

f(x) = 3x + 2/ 2x + 1

misal

u = 3x + 2 → u’ = 3

v = 2x + 1 → v’ = 2

maka,

f'(x) = u'v – uv' / v²

f'(x) = 3(2x + 1) – 2(3x + 2) / (2x + 1)²

f'(x) = (6x + 3 – 6x – 4) / (2x + 1)²

f'(x) = -1/ (2x + 1)²