Tolong dong temen temen bantuin kerjain NGASAL:LAPOR

Tolong dong temen temen bantuin kerjain NGASAL:LAPOR

Jawab:

Penjelasan dengan langkah-langkah:

soal 3

lim x-> -2 {x² + 16x +28 }/ { x² -8x – 20}

lim x-> -2 { (x +2)(x +14)} / { ( x+2)(x – 10)}

lim x-> -2 {x + 14}/ { x -10}

x= – 2 , L = 12/-12 = -1

soal4

lim(x -> -3) { 2x² + 5x – 3} / {x² + x – 6}

lim(x -> -3) { (x + 3)(2x- 1)} / {(x + 3)(x – 2)}

lim(x -> -3) { 2x – 1}/ {x – 2}

x = – 3 , L= {2(-3) – 1 } / {-3-2} = -7/-5 = 7/5

soal 5

$sf lim_{xto 3} dfrac{x-2}{3 - sqrt{x^2 + 5}}\\\= sf lim_{xto 3} dfrac{(x-2)(3+3)}{9 - x^2 - 5}}\\\= sf lim_{xto 3} dfrac{(x-2)(6)}{4 - x^2 }}\\\= sf lim_{xto 3} dfrac{(x-2)(6)}{(2- x)(2+ x)}\\\= sf lim_{xto 3} dfrac{(x-2)(6)}{-(x- 2) (2 + x)}\\\= sf lim_{xto 3} dfrac{(6)}{-(2 + x)}, untuk x = 3 to L = - dfrac{6}{5}$

Gambar Jawaban

Jawaban:

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Gambar Jawaban