Tolong jawab……………

integral

∫2x(1 – x²)⁴ dx [0 -1]

= ∫2x (1 – x²)⁴ d(1 – x²) / (-2x)

= -1/5 (1 – x²)⁵

= -1/5 ((1 – 0²)⁵ – (1 – (-1)²)⁵)

= -1/5 (1 – 0)

= -1/5