Tolong jawab essay yg 2 dan 3

Penjelasan dengan langkah-langkah:

2.) AB=BC=CD=DE= 2 cm, AT =5 cm

mencari TB

TB²= AT² + AB ²

TB =√AT² +AB²

=√5² +2²

= √25 +4

=√29 cm

TC²= TB²+BC²

TC = √(√29)² + 2²

=√ 29+4

= √33 cm

TD²= TC²+CD²

TD = √(√33)² + 2²

= √33+ 4

= √37 cm

panjang TE

= TD² + DE²

= √(√37)² + 2²

=√ 37 +4

= √41

=6,40 cm

3.)

d1 = 8+8+4 = 20 cm, r 1= ½x 20 = 10 cm

d2= 8 cm, r= ½x 8 = 4 cm

L. ½lingkaran 1

=½x π r²

= ½x 3,14 x 10×10

= ½x 314

=157 cm²

L. ½ lingkaran = 2

= 2 (½x π r²)

= 2 (½x 3,14 x 5 x5)

=2(1,57 x 25)

=2×39,25

=78,5 cm²

Luas yg diarsir

= L 1 – L 2

= 157 -78,5

=78,5 cm²