Tolong jawab kak plisss​

Jawaban:

1. B. {(-2,2)}

2. A. {(4,-5)}

Penjelasan dengan langkah-langkah:

1. x + 2y = 6 dan x + 2 = 0

metode eliminasi

x + 2y = 6 (1) x + 2y = 6

x + 2 = 0 (1) x + 2 = 0

————— –

4y = 6

y = 6 – 4

y = 2

metode subtitusi

x + 2 = 0

x + 2(1) = 0

x + 2 = 0

x = 0 – 2

x = -2

HP = {(-2,2)}

2. 2x – y = 3 dan y = -5

metode eliminasi

2x – y = 3 (1) 2x – y = 3

y = -5 (1) y = -5

—————— –

2x = 8

x = 8 : 2

x = 4

metode substitusi

y = -5

HP = {(4,-5)}

semoga membantu