Tolong jawab no.4 yaah please..

A. < EBA + <ABD = 180°
<ABD + <DCB = 180°
<DCB + <CBE = 180°
<CBE + < EBA = 180°
b. <ABE = < DBC = bertolak belakang = 60°
< ABE + <ABD + <CBD + <CBE = 360°
360 °- 2(60)° = 360° – 120° = 240 °/2=120°
jadi < ABD = < CBE = bertolak belakang =
120°