Segitiga ABC siku-siku di A,panjang AB=6cm,AC=8cm, maka keliling segitiga ABC adalh…..
Tolong jawab sama caranya
AB = 6 cm
AC = 8 cm
CB² = 6² + 8²
CB²= 36+64=100
CB = 10
K = AB +AC + CB
=6+8+10=24
BC = AC*+AB*
BC= 8* + 6*
BC = akar 64+36
BC = akar 100
BC = 10.
rumus keliling segitiga.
a+b+c = 10+8+6
= 24