Tolong jawabannya pliis
jawaban Super Master
a)
y – 1 = – ½ (x + 6)
2y – 2 = – x – 6
x + 2y + 4 = 0
b)
m = ∆y/∆x = 4/4
pGS = y – 4 = (x + 2)
y – x – 6 = 0
x – y + 6 = 0
Tolong jawabannya pliis
jawaban Super Master
a)
y – 1 = – ½ (x + 6)
2y – 2 = – x – 6
x + 2y + 4 = 0
b)
m = ∆y/∆x = 4/4
pGS = y – 4 = (x + 2)
y – x – 6 = 0
x – y + 6 = 0