TOLONg YAaa pake rumusnya gabole asal jawab lim sin 2x per sin x , x mendekati 0.

TOLONg YAaa pake rumusnya gabole asal jawab
lim sin 2x per sin x , x mendekati 0.

Jawaban Terkonfirmasi

$lim_{x to 0} frac{sin2x}{sinx}=lim_{n to 0} frac{2sinxcosx}{sinx}\\ =lim_{x to 0} frac{2sinxcosx}{sinx} . frac{x}{x}\\ =lim_{x to 0} frac{2sinxcosx}{x} . frac{x}{sinx}\\ =lim_{x to 0} 2cosx . frac{sinx}{x} . frac{x}{sinx}\\ =lim_{x to 0} 2cosx . lim_{x to 0}frac{sinx}{x} . lim_{x to 0}frac{x}{sinx}\\ =(2cos(0))(1)(1)\ =2$