Tolong yah, kimia nih​

Penjelasan:

1. dik : m H2SO4 = 4.9 g

Konsentrasi H2SO4 (M H2SO4) = 0.25 M

dit, : volume air (V) = ?

jb :

– Cari Mr H2SO4 :

Mr = (2*H) + (1 * S) + (4 * O)

= (2 * 1) + ( 1* 32) + ( 4 * 16 )

= 2 + 32 + 64

= 98

– Cari n H2SO4 :

n = m / Mr

n = 4.9 g / 98 g/mol

n = 0.05 mol

– Cari V air :

V = n/M

V = 0.05 mol / 0.25 M

V = 0.2 L

V = 200 mL (E)

2. Dik : m urea = 6 g

m air = 90 g

Dit : X urea

jb :

Mr urea = 60

Mr air = 18

– n urea :

n = m / mr

n = 6 g / 60 g/mol

n = 0.1 mol

– n air

n = m / mr

n = 90/18

n = 5

maka :

X urea = nt/np + nt

= 0.1/5+0.1

= 0.1 / 5.01

= 0.02 (B)

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