Tolonggg yaa pakai cara
Jawaban:
4 M
Penjelasan:
Mr CO(NH2)2 = 60
V = 500 ml ~ 0,5 L
mol CO(NH2)2 = massa / Mr
=> 120 / 60
=> 2 mol
M = n / V
M = 2 / 0,5
M = 4 M
Tolonggg yaa pakai cara
Jawaban:
4 M
Penjelasan:
Mr CO(NH2)2 = 60
V = 500 ml ~ 0,5 L
mol CO(NH2)2 = massa / Mr
=> 120 / 60
=> 2 mol
M = n / V
M = 2 / 0,5
M = 4 M