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3a) y = 3x + 4
m1 = 3
sejajar = m1 = m2 = 3
y – y1 = m (x – X1)
y – 1 = 3 ( x – 1)
y – 1 = 3x – 3
y = 3x – 3 + 1
y = 3x – 2

3c) 2y + 6x – 12 = 0
2y = – 6x + 12
y = – 3x + 6
m1 = – 3 = m2
y – y1 = m (x – X1)
y – 1 = – 3(x – 5)
y – 1 = – 3x + 5
y = – 3x + 5 + 1
y = – 3x + 6

4b) 2x + y – 5 = 0
y = – 2x + 5
m1 = – 2
syarat tegak lurus m1 . m2 = – 1
– 2 . m2 = – 1
m2 = ½
y – y1 = m (x – X1)
y – 6 = ½(x – 2)
y – 6 = ½x – 1
y = ½x – 1 + 6
y = ½x + 5

4d) y = x
m1 = 1
m1 . m2 = – 1
1 . m2 = – 1
m2 = – 1
y – y1 = m (x – X1)
y + 8 = – 1(x – 4)
y = -x + 4 – 8
y = – x – 4