Tolongin tentuin nilai yang a sama b​

3x² + nx + 4 = 0

(1/x₁) + (1/x₂) = 5

(x₁ + x₂) / x₁x₂ = 5

(x₁ + x₂) = 5x₁x₂

-n : 3 = 5(4/3)

-n = 15(4/3)

-n = 5(4)

-n = 20

n = -20

x₁² + x₂²

= (x₁ + x₂)² – 2x₁x₂

= (20/3)² – 2(4/3)

= (400/9) – (8/3)

= (400/9) – (24/9)

= 376/9

semoga membantu