Turunan pertama dari fungsi f(x) =3x² (2x – 5) pangkat 6 adalah f'(x) = …..

U = 3x²
u' = 6x
v = 2x-5)^6
v' = 6.2 (2x-5)^5
v' = 12 (2x-5)^5
6x (2x-5)^6 + 3x²(12 (2x-5)^5
= 6x(2x-5) + 36x² (2x-5)^5
= 12x² -30x + 36x² (2x-5)^5
= 48x² – 30x (2x-5)^5
= 6x(8x -5) (2x-5)^5

~DiFerEnSiaL

f(x) = 3x² (2x – 5)^6

f'(x) = u'v + uv'

f'(x) = 6x (2x – 5)^6 + 3x² ( 12(2x – 5)^5 )

f'(x) = 6x(2x – 5)^6 + 36x² (2x – 5)^5

f'(x) = 6x (2x – 5)^5 [(2x – 5) + 6x]

f'(x) = 6x (2x – 5)^5 (2x – 5 + 6x)

f'(x) = 6x (2x – 5)^5 (8x – 5)

f'(x) = 6x (8x – 5)(2x – 5)^2

OPTION B