Turunan pertama dari fungsi f(x)= 3x²-5/x-6

Kelas 11 Matematika
Bab Turunan

f(x) = (3x² – 5)/(x – 6)
f'(x) = (6x (x – 6) – (3x² – 5) . 1)/(x – 6)²
f'(x) = (6x² – 36x – 3x² + 5)/(x – 6)²
f'(x) = (3x² – 36x + 5)/(x² – 12x + 36)

Misalkan U(x) = 3x² -5 dan V(x) = x – 6
U'(x)= 6x. V'(x) = 1
Y' = [U'(x)V(x) – U(x)V'(x)]/[V(x)]²
= [6x(x-6)-(3x²-5)(1)]/(x-1)²
= [6x²-36x-3x²+5]/(x²-2x +1)
= [3x²-36x +5]/(x²-2x +1)