Turunan pertama dari f(x) = (x – 2) (x + 3

F(x) = (x-2)(x+3)
f(x) = x² + x – 6
f'(x) = 2x + 1

atau
y = (x – 2) (x + 3)
f(x) = x – 2 , f'(x) = 1
g(x) = (x + 3), g'(x) =1

y' = f'(x) g(x) + g'(x) f(x)
y'= 1(x + 3) + 1(x-2)
y' = x + 3 +x – 2
y' = 2x + 1