Turunana secan (ax+b) = …. Tolong Pakai pembuktian yaa..

Sec(ax + b) = 1/(cos(ax + b))

misal,

t = ax + b
dt/dx = a

v = cos t
dv/dt = -sin t

dv/dx = dv/dt * dt/dx
v' = -sin t * a
v' = -a.sin(ax + b)

misal,

u = 1
u' = 0
v = cos(ax + b)
v' = -a.sin(ax + b)

y' = (u'v – uv')/v^2
= (0.cos(ax + b) – (1)(-a.sin(ax + b))/(cos²(ax + b))
= a.sin(ax + b)/cos²(ax + b)
= a.tan(ax+b).sec(ax+b)