dalam bentuk umumnya. pls
a.x² + 4x = 9
b. x(x – 4) = 0
c. (x + 1)(x – 7) = 0
d. 2(x² – 4x + 9) = 0
e. 2x² + 4x = x² – 5x + 9
Ubahlah persamaan kuadrat berikut ke
Jawaban:
Bentuk umum persamaan kuadrat:
ax² + bx + c = 0
a.x² + 4x = 9
=> x² + 4x – 9 = 0
b. x(x – 4) = 0
=> x² – 4x + 0 = 0
c. (x + 1)(x – 7) = 0
=> x² – 7x + x – 7 = 0
=> x² – 6x – 7 = 0
d. 2(x² – 4x + 9) = 0
=> (2 × x²) – (2 × 4x) + (2 × 9) = 0
=> 2x² – 8x + 18 = 0
e. 2x² + 4x = x² – 5x + 9
=> 2x² + 4x – x² + 5x – 9
=> 2x² – x² + 4x + 5x – 9
=> x² + 9x – 9 = 0
semoga membantu,
met belajar skuy 🙂