Ubahlah titik E ( – 3 , – 3 ) menjadi koordinat kutub​

koordinat kartesius → koordinat kutub

(x,y) → (r,a)

r = √(x² + y²)

a = arc tan (y/x)

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E(-3,-3) → kuadran III (-x,-y)

r = √((-3)² + (-3)²)

r = √(2 × 9)

r = 3√2

a = arc tan (-3/-3)

a = arc tan (1)

a = 180° + 45°

a = 225°

E(–3 , –3) → E(3√2 , 225°)