W1 = 30N W2 = 15 NHitung besar gaya tegangan talinya

Diketahui :

W1= 30N

W2 = 15N

<=> katrol bergerak ke arah W2. karena W1>W2

Ditanya :

gaya tegangan tali (T1+T2)

jawab:

(1)

W1 = m1 g

30=m1 (10)

m1= 30/10

m1= 3 Kg

W2 = m2 g

15 =m2 (10)

m2 = 15/10

m2 = 1,5 Kg

a= W/m

a= (30+15)/(3+1,5)

a= 45/4,5

a=

(2)

ΣF = ma

W1 – T1 = m1 a

(30) – T1 = (3) a

T1 = 30 – 3a

ΣF = ma

T2 – W2 = m2 a

T2 – (15) = (1,5) a

T2 = 15 + 1,5a

(3)

T1 = T2

30 – 3a = 15 + 1,5a

30 – 15 = 1,5a + 3a

15 = 4,5a

a = 15/4,5

a = 150/45

a = 10/3

(4)

subtitusi kan

a=10/3

T1 = 30-3(10/3)

T1 = 30-10

T1 = 20 N

T2 = 15+1,5(10/3)

T2 = 15 + 5

T2 = 20 N

Tegangan total = T1+T2 = 40N

semoga membantu