X1 dan x2 adalah akar akar persamaan kuadrat x”+5x+2k-1=0. Jika 1/x1 + 1/x2 =2/5 nilai k adalah…
Jawaban Terkonfirmasi
1/x1 + 1/x2 = (x1 + x2) /(x1x2) = 2/5
= (-b/a)/(c/a) 2/5
= (-5/1)/(2k -1/1) = 2/5
= 5(-5) = 2(2k -1)
-25 = 4k -2
4k = -23
k = 23/4 = 5 3/4