|x+4| > |3x+2| - Universityku

tolong dong kak saya kebingungan nih….

soal pertidaksamaan nilai mutlak

|x+4| > |3x+2|

Penjelasan dengan langkah-langkah:

$|x + 4| > |3x + 2| \ ( {x + 4)}^{2} > ( {3x + 2)}^{2} \ = {x}^{2} + 8x + 16 > 9 {x}^{2} + 12x + 4 \ {x}^{2} - 9 {x}^{2} + 8x - 12x + 16 - 4 > 0 \ - 8 {x}^{2} - 4x + 12 > 0 \ 2{x}^{2} + x - 3 < 0 \ (2x + 3)(x - 1) < 0 \ 2x + 3 = 0 \ 2x = - 3 \ x = - frac{ 3}{2}$

$x - 1 = 0 \ x = 1$

$- frac{3}{2} < x < 1$