Y = 1 + cos x / – sin x dy/dx=…….

Jawab

y = (1 + cos x) / (- sin x)

u = 1 + cosx 
u' = – sin x

v = – sin x
v' = – cos x

y = u/v
y' = (u' v + uv') / (v²)

y' = {(-sin x)(-sin x) + (1+cos x)(-cos x)}/ (- sin x)²
y' = {sin² x – cos x  – cos² x} / (sin² x)

y' = sin² x/ sin²x  – cos x / sin² x – cos²x /.sin² x
y' = 1 – cos x . csc x -  cot² x