Y^2 = x-1
(x-3)^2 + y^2 =4
Jawaban Terkonfirmasi
Substitusi y² = x – 1 ke persamaan
(x – 3)² + y² = 4
(x – 3)² + x – 1 – 4 = 0
x² – 6x + 9 + x – 5 = 0
x² – 5x + 4 = 0
(x – 1)(x – 4) = 0
utk x = 1 ⇒ y = 0
utk x = 4 ⇒ y = - √3 atau √3
Y^2 = x-1
(x-3)^2 + y^2 =4
Substitusi y² = x – 1 ke persamaan
(x – 3)² + y² = 4
(x – 3)² + x – 1 – 4 = 0
x² – 6x + 9 + x – 5 = 0
x² – 5x + 4 = 0
(x – 1)(x – 4) = 0
utk x = 1 ⇒ y = 0
utk x = 4 ⇒ y = - √3 atau √3