³log(4x + 2)-³log( x-2)=2​

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³log(4x + 2)-³log( x-2)=2​

Penjelasan dengan langkah-langkah:

³log (4x + 2) – ³log (x – 2) = 2

³log ((4x + 2)/(x – 2)) = 2

(4x + 2)/(x – 2) = 3²

4x + 2 = 9 . (x – 2)

4x + 2 = 9x – 18

4x – 9x = -18 – 2

-5x = -20

x = -20/-5

x = 4

Syarat

4x + 2 > 0

4x > -2

x > -2/4

x > -1/2

x – 2 > 0

x > 2

Maka, x = 4

Detail Jawaban

Kelas 10

Mapel 2 – Matematika

Bab 1.1 – Bentuk Akar, Eksponen dan Logaritma

Kode Kategorisasi : 10.2.1.1

Jawaban:

semoga membantu………

Gambar Jawaban