∫(x²+e×-1/x)dx= - Universityku

tolong di beri rincian dari integral e itu berapa/jika memiliki rumus tertentu ,bisa di sertakan. terima kasih

∫(x²+e×-1/x)dx=

Jawab:

$displaystyle intleft(x^2+e^x-frac1xright),dx=int x^2,dx+int e^x,dx-intfrac1xright),dx\intleft(x^2+e^x-frac1xright),dx=frac1{2+1}x^{2+1}+e^x-ln x+C\intleft(x^2+e^x-frac1xright),dx=frac13x^3+e^x-ln x+C$

Beberapa konsep yang dipakai:

$displaystyletriangleright~int y_1pm y_2pmcdotspm y_n,dx=int y_1,dxpmint y_2,dxpmcdotspmint y_n,dx\triangleright~int ax^n,dx=frac{a}{n+1}x^{n+1}+C~;~nneq-1\triangleright~int e^x,dx=e^x+C\triangleright~intfrac1x,dx=ln x+C$